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Preparation for the 1z1-809 exam typically involves studying the exam objectives, reading related textbooks, and practicing with sample questions and simulations. Oracle also offers official training courses that can help prepare candidates for the exam. These courses cover all the topics tested on the 1z1-809 exam and provide hands-on lab exercises to reinforce learning.
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The Oracle 1z0-809 exam consists of 80 multiple-choice questions that need to be completed within 150 minutes. 1z0-809 exam is offered through Pearson VUE and can be taken at any authorized testing center. A passing score of 65% or above is required to obtain the certification, which is valid for a period of three years. The Oracle 1z1-809 Exam is an essential certification for any Java developer who wants to take their skills to the next level and demonstrate their proficiency to potential employers.
To be eligible for the 1z0-809 Exam, you must have a solid understanding of the Java programming language and its core concepts. You must have passed the 1z0-808 exam, which is the first-level exam in the Java SE 8 certification path. Additionally, you must have hands-on experience in developing Java applications using the latest Java SE 8 features.
Oracle Java SE 8 Programmer II Sample Questions (Q98-Q103):
NEW QUESTION # 98
Given:
and
Which interface from the java.util.functionpackage should you use to refactor the class Txt?
- A. Predicate
- B. Function
- C. Supplier
- D. Consumer
Answer: C
Explanation:
Explanation/Reference:
Reference: https://docs.oracle.com/javase/8/docs/api/java/util/function/package-summary.html
NEW QUESTION # 99
Given:
and the code fragment:
What is the result?
- A. Java EE
Java ME - B. A compilation error occurs.
- C. [Java ME: Jessy:Chicago, Java ME: Mark:Chicago]
[Java EE: Helen:Houston] - D. [Java EE: Helen:Houston]
[Java ME: Jessy:Chicago, Java ME: Mark:Chicago]
Answer: B
NEW QUESTION # 100
Assume customers.txt is accessible and contains multiple lines.
Which code fragment prints the contents of the customers.txt file?
- A. Stream<Path> stream = Files.list (Paths.get ("customers.txt"));stream.forEach( c) -> System.out.println (c));
- B. Stream<String> stream = Files.find (Paths.get ("customers.txt"));stream.forEach((String c) -> System.
out.println(c)); - C. Stream<Path> stream = Files.find (Paths.get ("customers.txt"));stream.forEach( c) -> System.out.println (c));
- D. Stream<String> lines = Files.lines (Paths.get ("customers.txt"));lines.forEach( c) -> System.out.println (c));
Answer: D
NEW QUESTION # 101
Given the code fragment:
Path path1 = Paths.get("/app/./sys/");
Path res1 = path1.resolve("log");
Path path2 = Paths.get("/server/exe/");
Path res1 = path1.resolve("/readme/");
System.out.println(res1);
System.out.println(res2);
What is the result?
- A. /app/./sys/log
/ server/exe/readme - B. /app/log/sys
/ server/exe/readme - C. /app/./sys/log
/ readme - D. /app/sys/log
/readme/server/exe
Answer: A
NEW QUESTION # 102
Given the code fragment:
What is the result?
- A. text1text2text2text3
- B. [text1, text2]
- C. text1
- D. text1text2
Answer: D
NEW QUESTION # 103
......
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